Daniil Medvedev qualified for the semi-finals of the Dubai Tennis Championships after defeating Jenson Brooksby in straight sets.

It was a routine victory for the third seed, who won 6-2 6-1 in just 58 minutes to book his spot in the last four.

It was a ruthless start from Medvedev, who converted his first break point opportunity in the opening game as he eventually moved into a 3-1 lead.

Though Brooksby saved a break point in the fifth game, Medvedev broke again on his way to winning the first set, while starting the second in the exact same fashion.

Medvedev eventually clinched victory with his third match point, while taking Brooksby's serve three times in the second.

68 - Since 2017, when Daniil Medvedev reached his first semi-final at ATP-level in Chennai, only Alexander Zverev and Novak Djokovic have managed more semi-finals in such events than Medvedev (68 - including ATP-NextGen). Marching. #ddftennis | @DDFTennis @atptour pic.twitter.com/3Zj5XyFSvy

— OptaAce (@OptaAce) February 26, 2026

The former US Open champion will face Felix Auger-Aliassime in the last four after the Canadian defeated Jiri Lehecka 6-3 7-6 (7-2).

On the other side of the draw, Andrey Rublev cruised to a 6-2 6-4 victory over Arthur Rinderknech in 77 minutes.

Rublev will face Tallon Griekspoor for a place in the final after the latter overcame Jakub Mensik 6-3 3-6 6-2.

Data Debrief: Another semi-final for Medvedev on the horizon

Since 2017, when Medvedev reached his first semi-final at ATP-level in Chennai, only Alexander Zverev and Novak Djokovic have managed more semi-finals in such events than Medvedev (68 - including ATP-NextGen).

Medvedev was very impressive on serve against Brooksby, winning 77% of his first-serve points to the American's 47%, and firing in seven aces to his counterpart's 0.